Web11 Feb 2024 · Best answer Given function f: R+ → [−5, ∞) given by f (x) = 9x2 + 6x – 5 Let us show that f is invertible. Injectivity of f: Let x and y be any two elements of domain (R+), Such that f (x) = f (y) ⇒ 9x2 + 6x – 5 = 9y2 + 6y − 5 ⇒ 9x2 + 6x = 9y2 + 6y ⇒ x = y (As, x, y ∈ R+) Therefore, f is one-one. Surjectivity of f: Let y is in the co domain (Q) Web14 Apr 2024 · In order to study rapidly rotating NS in f(R, T) gravity, we start by briefly discussing the main aspects of this modified theory of gravity.. In 2011, Harko et al. [] proposed the theory of gravity f(R, T), where the gravitational Lagrangian is an arbitrary function of the Ricci scalar R and of the trace of the energy–momentum tensor T.The …

6.1: Relations on Sets - Mathematics LibreTexts

Web29 Dec 2024 · If a function f(x) is defined ∀ x ∈ R such that ∫f(x)dx for x ∈ [0, a], a R+ exist. ... 1 answer. Let f : [1, ∞) →[2, ∞) be a differentiable function such that f(1) = 2. If 6∫f(t)dt t ∈[1, x] = 3xf(x) - x^3 for all x ≥ 1, Webfunction to consider, which means that we can take jBj= 1, say b= fbg. But then if fis a function from Ato B, we see that f(a 1) = bas well as f(a 2) = bsince bis the only element a … teori hierarki perundang undangan

Answered: 3. A) For a function f: R → R defined… bartleby

WebIt is given that f:R⋅→R⋅ is defined by f(x)= x1. One-one. f(x)=f(y) ⇒ x1= y1 ⇒x=y ∴f is one-one. Onto: It is clear that for y∈R⋅, there exists x= y1∈R⋅ (Exists as y ==0) such that f(x)= y11 = y … WebVariable R cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by RR_{1}R_{2}, the least common multiple of R,R_{1},R_{2}. ... Multiply both … WebA function f from X to Y. The set of points in the red oval X is the domain of f. Graph of the real-valued square root function, f ( x) = √x, whose domain consists of all nonnegative real … teori hierarki peraturan perundang-undangan